x^2=(-5-4x)/2

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Solution for x^2=(-5-4x)/2 equation: 


x in (-oo:+oo)

x^2 = (-(4*x)-5)/2 // - (-(4*x)-5)/2

x^2-((-(4*x)-5)/2) = 0

x^2-((-4*x-5)/2) = 0

(-1*(-4*x-5))/2+x^2 = 0

(-1*(-4*x-5))/2+(2*x^2)/2 = 0

2*x^2-1*(-4*x-5) = 0

2*x^2+4*x+5 = 0

2*x^2+4*x+5 = 0

2*x^2+4*x+5 = 0

DELTA = 4^2-(2*4*5)

DELTA = -24

DELTA < 0

1 = 0

1/2 = 0

1/2 = 0 // * 2

1 = 0

x belongs to the empty set

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